4(y-2)=7y+2-2(-6y-1)

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Solution for 4(y-2)=7y+2-2(-6y-1) equation:



4(y-2)=7y+2-2(-6y-1)
We move all terms to the left:
4(y-2)-(7y+2-2(-6y-1))=0
We multiply parentheses
4y-(7y+2-2(-6y-1))-8=0
We calculate terms in parentheses: -(7y+2-2(-6y-1)), so:
7y+2-2(-6y-1)
determiningTheFunctionDomain 7y-2(-6y-1)+2
We multiply parentheses
7y+12y+2+2
We add all the numbers together, and all the variables
19y+4
Back to the equation:
-(19y+4)
We get rid of parentheses
4y-19y-4-8=0
We add all the numbers together, and all the variables
-15y-12=0
We move all terms containing y to the left, all other terms to the right
-15y=12
y=12/-15
y=-4/5

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