4(y-3)+13=4y+1

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Solution for 4(y-3)+13=4y+1 equation: 


Simplifying
4(y + -3) + 13 = 4y + 1

Reorder the terms:
4(-3 + y) + 13 = 4y + 1
(-3 * 4 + y * 4) + 13 = 4y + 1
(-12 + 4y) + 13 = 4y + 1

Reorder the terms:
-12 + 13 + 4y = 4y + 1

Combine like terms: -12 + 13 = 1
1 + 4y = 4y + 1

Reorder the terms:
1 + 4y = 1 + 4y

Add '-1' to each side of the equation.
1 + -1 + 4y = 1 + -1 + 4y

Combine like terms: 1 + -1 = 0
0 + 4y = 1 + -1 + 4y
4y = 1 + -1 + 4y

Combine like terms: 1 + -1 = 0
4y = 0 + 4y
4y = 4y

Add '-4y' to each side of the equation.
4y + -4y = 4y + -4y

Combine like terms: 4y + -4y = 0
0 = 4y + -4y

Combine like terms: 4y + -4y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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