4(y-3)+2(y+4)=20

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Solution for 4(y-3)+2(y+4)=20 equation:


Simplifying
4(y + -3) + 2(y + 4) = 20

Reorder the terms:
4(-3 + y) + 2(y + 4) = 20
(-3 * 4 + y * 4) + 2(y + 4) = 20
(-12 + 4y) + 2(y + 4) = 20

Reorder the terms:
-12 + 4y + 2(4 + y) = 20
-12 + 4y + (4 * 2 + y * 2) = 20
-12 + 4y + (8 + 2y) = 20

Reorder the terms:
-12 + 8 + 4y + 2y = 20

Combine like terms: -12 + 8 = -4
-4 + 4y + 2y = 20

Combine like terms: 4y + 2y = 6y
-4 + 6y = 20

Solving
-4 + 6y = 20

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 4 + 6y = 20 + 4

Combine like terms: -4 + 4 = 0
0 + 6y = 20 + 4
6y = 20 + 4

Combine like terms: 20 + 4 = 24
6y = 24

Divide each side by '6'.
y = 4

Simplifying
y = 4

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