4(y-3)+2y=3y+6

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Solution for 4(y-3)+2y=3y+6 equation: 



4(y-3)+2y=3y+6

We move all terms to the left:

4(y-3)+2y-(3y+6)=0

We add all the numbers together, and all the variables

2y+4(y-3)-(3y+6)=0

We multiply parentheses

2y+4y-(3y+6)-12=0

We get rid of parentheses

2y+4y-3y-6-12=0

We add all the numbers together, and all the variables

3y-18=0

We move all terms containing y to the left, all other terms to the right

3y=18

y=18/3

y=6

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