4(y-3)+3=(y+4)

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Solution for 4(y-3)+3=(y+4) equation: 



4(y-3)+3=(y+4)

We move all terms to the left:

4(y-3)+3-((y+4))=0

We multiply parentheses

4y-((y+4))-12+3=0



We calculate terms in parentheses: -((y+4)), so:

(y+4)

We get rid of parentheses

y+4

Back to the equation:

-(y+4)



We add all the numbers together, and all the variables

4y-(y+4)-9=0

We get rid of parentheses

4y-y-4-9=0

We add all the numbers together, and all the variables

3y-13=0

We move all terms containing y to the left, all other terms to the right

3y=13

y=13/3

y=4+1/3

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