4(y-3)+3y=-(5y-21)

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Solution for 4(y-3)+3y=-(5y-21) equation:



4(y-3)+3y=-(5y-21)
We move all terms to the left:
4(y-3)+3y-(-(5y-21))=0
We add all the numbers together, and all the variables
3y+4(y-3)-(-(5y-21))=0
We multiply parentheses
3y+4y-(-(5y-21))-12=0
We calculate terms in parentheses: -(-(5y-21)), so:
-(5y-21)
We get rid of parentheses
-5y+21
Back to the equation:
-(-5y+21)
We add all the numbers together, and all the variables
7y-(-5y+21)-12=0
We get rid of parentheses
7y+5y-21-12=0
We add all the numbers together, and all the variables
12y-33=0
We move all terms containing y to the left, all other terms to the right
12y=33
y=33/12
y=2+3/4

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