4(y-3)+3y=-(5y-21)

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Solution for 4(y-3)+3y=-(5y-21) equation: 



4(y-3)+3y=-(5y-21)

We move all terms to the left:

4(y-3)+3y-(-(5y-21))=0

We add all the numbers together, and all the variables

3y+4(y-3)-(-(5y-21))=0

We multiply parentheses

3y+4y-(-(5y-21))-12=0



We calculate terms in parentheses: -(-(5y-21)), so:

-(5y-21)

We get rid of parentheses

-5y+21

Back to the equation:

-(-5y+21)



We add all the numbers together, and all the variables

7y-(-5y+21)-12=0

We get rid of parentheses

7y+5y-21-12=0

We add all the numbers together, and all the variables

12y-33=0

We move all terms containing y to the left, all other terms to the right

12y=33

y=33/12

y=2+3/4

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