4(y-3)+6y=8

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Solution for 4(y-3)+6y=8 equation: 



4(y-3)+6y=8

We move all terms to the left:

4(y-3)+6y-(8)=0

We add all the numbers together, and all the variables

6y+4(y-3)-8=0

We multiply parentheses

6y+4y-12-8=0

We add all the numbers together, and all the variables

10y-20=0

We move all terms containing y to the left, all other terms to the right

10y=20

y=20/10

y=2

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