4(y-3)+7(y+1)=28

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Solution for 4(y-3)+7(y+1)=28 equation:


Simplifying
4(y + -3) + 7(y + 1) = 28

Reorder the terms:
4(-3 + y) + 7(y + 1) = 28
(-3 * 4 + y * 4) + 7(y + 1) = 28
(-12 + 4y) + 7(y + 1) = 28

Reorder the terms:
-12 + 4y + 7(1 + y) = 28
-12 + 4y + (1 * 7 + y * 7) = 28
-12 + 4y + (7 + 7y) = 28

Reorder the terms:
-12 + 7 + 4y + 7y = 28

Combine like terms: -12 + 7 = -5
-5 + 4y + 7y = 28

Combine like terms: 4y + 7y = 11y
-5 + 11y = 28

Solving
-5 + 11y = 28

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + 11y = 28 + 5

Combine like terms: -5 + 5 = 0
0 + 11y = 28 + 5
11y = 28 + 5

Combine like terms: 28 + 5 = 33
11y = 33

Divide each side by '11'.
y = 3

Simplifying
y = 3

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