4(y-3)+7y=-35

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Solution for 4(y-3)+7y=-35 equation: 



4(y-3)+7y=-35

We move all terms to the left:

4(y-3)+7y-(-35)=0

We add all the numbers together, and all the variables

7y+4(y-3)+35=0

We multiply parentheses

7y+4y-12+35=0

We add all the numbers together, and all the variables

11y+23=0

We move all terms containing y to the left, all other terms to the right

11y=-23

y=-23/11

y=-2+1/11

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