4(y-3)-1=-3(-7y+5)-5y

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Solution for 4(y-3)-1=-3(-7y+5)-5y equation: 



4(y-3)-1=-3(-7y+5)-5y

We move all terms to the left:

4(y-3)-1-(-3(-7y+5)-5y)=0

We multiply parentheses

4y-(-3(-7y+5)-5y)-12-1=0



We calculate terms in parentheses: -(-3(-7y+5)-5y), so:

-3(-7y+5)-5y

We add all the numbers together, and all the variables

-5y-3(-7y+5)

We multiply parentheses

-5y+21y-15

We add all the numbers together, and all the variables

16y-15

Back to the equation:

-(16y-15)



We add all the numbers together, and all the variables

4y-(16y-15)-13=0

We get rid of parentheses

4y-16y+15-13=0

We add all the numbers together, and all the variables

-12y+2=0

We move all terms containing y to the left, all other terms to the right

-12y=-2

y=-2/-12

y=1/6

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