4(y-3)-2y=28

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Solution for 4(y-3)-2y=28 equation: 



4(y-3)-2y=28

We move all terms to the left:

4(y-3)-2y-(28)=0

We add all the numbers together, and all the variables

-2y+4(y-3)-28=0

We multiply parentheses

-2y+4y-12-28=0

We add all the numbers together, and all the variables

2y-40=0

We move all terms containing y to the left, all other terms to the right

2y=40

y=40/2

y=20

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