4(y-3)-2y=6y+12+2y

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Solution for 4(y-3)-2y=6y+12+2y equation: 



4(y-3)-2y=6y+12+2y

We move all terms to the left:

4(y-3)-2y-(6y+12+2y)=0

We add all the numbers together, and all the variables

4(y-3)-2y-(8y+12)=0

We add all the numbers together, and all the variables

-2y+4(y-3)-(8y+12)=0

We multiply parentheses

-2y+4y-(8y+12)-12=0

We get rid of parentheses

-2y+4y-8y-12-12=0

We add all the numbers together, and all the variables

-6y-24=0

We move all terms containing y to the left, all other terms to the right

-6y=24

y=24/-6

y=-4

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