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4(y-3)-3y=2(y-6)
We move all terms to the left:
4(y-3)-3y-(2(y-6))=0
We add all the numbers together, and all the variables
-3y+4(y-3)-(2(y-6))=0
We multiply parentheses
-3y+4y-(2(y-6))-12=0
We calculate terms in parentheses: -(2(y-6)), so:We add all the numbers together, and all the variables
2(y-6)
We multiply parentheses
2y-12
Back to the equation:
-(2y-12)
y-(2y-12)-12=0
We get rid of parentheses
y-2y+12-12=0
We add all the numbers together, and all the variables
-y=0
y=0/-1
y=0
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