4(y-3)-5=-3(-6y+3)-2y

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Solution for 4(y-3)-5=-3(-6y+3)-2y equation:



4(y-3)-5=-3(-6y+3)-2y
We move all terms to the left:
4(y-3)-5-(-3(-6y+3)-2y)=0
We multiply parentheses
4y-(-3(-6y+3)-2y)-12-5=0
We calculate terms in parentheses: -(-3(-6y+3)-2y), so:
-3(-6y+3)-2y
We add all the numbers together, and all the variables
-2y-3(-6y+3)
We multiply parentheses
-2y+18y-9
We add all the numbers together, and all the variables
16y-9
Back to the equation:
-(16y-9)
We add all the numbers together, and all the variables
4y-(16y-9)-17=0
We get rid of parentheses
4y-16y+9-17=0
We add all the numbers together, and all the variables
-12y-8=0
We move all terms containing y to the left, all other terms to the right
-12y=8
y=8/-12
y=-2/3

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