4(y-3)-6(y+1)=4(4y+4)-2(8+6y)

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Solution for 4(y-3)-6(y+1)=4(4y+4)-2(8+6y) equation: 



4(y-3)-6(y+1)=4(4y+4)-2(8+6y)

We move all terms to the left:

4(y-3)-6(y+1)-(4(4y+4)-2(8+6y))=0

We add all the numbers together, and all the variables

4(y-3)-6(y+1)-(4(4y+4)-2(6y+8))=0

We multiply parentheses

4y-6y-(4(4y+4)-2(6y+8))-12-6=0



We calculate terms in parentheses: -(4(4y+4)-2(6y+8)), so:

4(4y+4)-2(6y+8)

We multiply parentheses

16y-12y+16-16

We add all the numbers together, and all the variables

4y

Back to the equation:

-(4y)



We add all the numbers together, and all the variables

-6y-18=0

We move all terms containing y to the left, all other terms to the right

-6y=18

y=18/-6

y=-3

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