4(y-3)-6=-4(-3y+8)-4y

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Solution for 4(y-3)-6=-4(-3y+8)-4y equation: 



4(y-3)-6=-4(-3y+8)-4y

We move all terms to the left:

4(y-3)-6-(-4(-3y+8)-4y)=0

We multiply parentheses

4y-(-4(-3y+8)-4y)-12-6=0



We calculate terms in parentheses: -(-4(-3y+8)-4y), so:

-4(-3y+8)-4y

We add all the numbers together, and all the variables

-4y-4(-3y+8)

We multiply parentheses

-4y+12y-32

We add all the numbers together, and all the variables

8y-32

Back to the equation:

-(8y-32)



We add all the numbers together, and all the variables

4y-(8y-32)-18=0

We get rid of parentheses

4y-8y+32-18=0

We add all the numbers together, and all the variables

-4y+14=0

We move all terms containing y to the left, all other terms to the right

-4y=-14

y=-14/-4

y=3+1/2

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