4(y-3)-8y=-8

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Solution for 4(y-3)-8y=-8 equation:



4(y-3)-8y=-8
We move all terms to the left:
4(y-3)-8y-(-8)=0
We add all the numbers together, and all the variables
-8y+4(y-3)+8=0
We multiply parentheses
-8y+4y-12+8=0
We add all the numbers together, and all the variables
-4y-4=0
We move all terms containing y to the left, all other terms to the right
-4y=4
y=4/-4
y=-1

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