4(y-3)-y=3(y-4)

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Solution for 4(y-3)-y=3(y-4) equation:


Simplifying
4(y + -3) + -1y = 3(y + -4)

Reorder the terms:
4(-3 + y) + -1y = 3(y + -4)
(-3 * 4 + y * 4) + -1y = 3(y + -4)
(-12 + 4y) + -1y = 3(y + -4)

Combine like terms: 4y + -1y = 3y
-12 + 3y = 3(y + -4)

Reorder the terms:
-12 + 3y = 3(-4 + y)
-12 + 3y = (-4 * 3 + y * 3)
-12 + 3y = (-12 + 3y)

Add '12' to each side of the equation.
-12 + 12 + 3y = -12 + 12 + 3y

Combine like terms: -12 + 12 = 0
0 + 3y = -12 + 12 + 3y
3y = -12 + 12 + 3y

Combine like terms: -12 + 12 = 0
3y = 0 + 3y
3y = 3y

Add '-3y' to each side of the equation.
3y + -3y = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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