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4(y-3)=-4(-y+3)
We move all terms to the left:
4(y-3)-(-4(-y+3))=0
We add all the numbers together, and all the variables
4(y-3)-(-4(-1y+3))=0
We multiply parentheses
4y-(-4(-1y+3))-12=0
We calculate terms in parentheses: -(-4(-1y+3)), so:We get rid of parentheses
-4(-1y+3)
We multiply parentheses
4y-12
Back to the equation:
-(4y-12)
4y-4y+12-12=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0
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