4(y-3)=-6(5+y)

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Solution for 4(y-3)=-6(5+y) equation:



4(y-3)=-6(5+y)
We move all terms to the left:
4(y-3)-(-6(5+y))=0
We add all the numbers together, and all the variables
4(y-3)-(-6(y+5))=0
We multiply parentheses
4y-(-6(y+5))-12=0
We calculate terms in parentheses: -(-6(y+5)), so:
-6(y+5)
We multiply parentheses
-6y-30
Back to the equation:
-(-6y-30)
We get rid of parentheses
4y+6y+30-12=0
We add all the numbers together, and all the variables
10y+18=0
We move all terms containing y to the left, all other terms to the right
10y=-18
y=-18/10
y=-1+4/5

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