4(y-3)=2(y+1)-6

Solution for 4(y-3)=2(y+1)-6 equation:

4(y-3)=2(y+1)-6

We move all terms to the left:

4(y-3)-(2(y+1)-6)=0

We multiply parentheses

4y-(2(y+1)-6)-12=0


We calculate terms in parentheses: -(2(y+1)-6), so:

2(y+1)-6

We multiply parentheses

2y+2-6

We add all the numbers together, and all the variables

2y-4

Back to the equation:

-(2y-4)


We get rid of parentheses

4y-2y+4-12=0

We add all the numbers together, and all the variables

2y-8=0

We move all terms containing y to the left, all other terms to the right

2y=8

y=8/2

y=4