4(y-3)=3(y+2(y-2))

Solution for 4(y-3)=3(y+2(y-2)) equation:

Simplifying
4(y + -3) = 3(y + 2(y + -2))

Reorder the terms:
4(-3 + y) = 3(y + 2(y + -2))
(-3 * 4 + y * 4) = 3(y + 2(y + -2))
(-12 + 4y) = 3(y + 2(y + -2))

Reorder the terms:
-12 + 4y = 3(y + 2(-2 + y))
-12 + 4y = 3(y + (-2 * 2 + y * 2))
-12 + 4y = 3(y + (-4 + 2y))

Reorder the terms:
-12 + 4y = 3(-4 + y + 2y)

Combine like terms: y + 2y = 3y
-12 + 4y = 3(-4 + 3y)
-12 + 4y = (-4 * 3 + 3y * 3)
-12 + 4y = (-12 + 9y)

Add '12' to each side of the equation.
-12 + 12 + 4y = -12 + 12 + 9y

Combine like terms: -12 + 12 = 0
0 + 4y = -12 + 12 + 9y
4y = -12 + 12 + 9y

Combine like terms: -12 + 12 = 0
4y = 0 + 9y
4y = 9y

Solving
4y = 9y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-9y' to each side of the equation.
4y + -9y = 9y + -9y

Combine like terms: 4y + -9y = -5y
-5y = 9y + -9y

Combine like terms: 9y + -9y = 0
-5y = 0

Divide each side by '-5'.
y = 0

Simplifying
y = 0