4(y-3)=6(y-1)

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Solution for 4(y-3)=6(y-1) equation: 



4(y-3)=6(y-1)

We move all terms to the left:

4(y-3)-(6(y-1))=0

We multiply parentheses

4y-(6(y-1))-12=0



We calculate terms in parentheses: -(6(y-1)), so:

6(y-1)

We multiply parentheses

6y-6

Back to the equation:

-(6y-6)



We get rid of parentheses

4y-6y+6-12=0

We add all the numbers together, and all the variables

-2y-6=0

We move all terms containing y to the left, all other terms to the right

-2y=6

y=6/-2

y=-3

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