4(y-3)=6y-7

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Solution for 4(y-3)=6y-7 equation: 



4(y-3)=6y-7

We move all terms to the left:

4(y-3)-(6y-7)=0

We multiply parentheses

4y-(6y-7)-12=0

We get rid of parentheses

4y-6y+7-12=0

We add all the numbers together, and all the variables

-2y-5=0

We move all terms containing y to the left, all other terms to the right

-2y=5

y=5/-2

y=-2+1/2

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