4(y-32)-8=8y-12

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Solution for 4(y-32)-8=8y-12 equation: 



4(y-32)-8=8y-12

We move all terms to the left:

4(y-32)-8-(8y-12)=0

We multiply parentheses

4y-(8y-12)-128-8=0

We get rid of parentheses

4y-8y+12-128-8=0

We add all the numbers together, and all the variables

-4y-124=0

We move all terms containing y to the left, all other terms to the right

-4y=124

y=124/-4

y=-31

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