4(y-4)+12y=14y-1(20)

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Solution for 4(y-4)+12y=14y-1(20) equation: 



4(y-4)+12y=14y-1(20)

We move all terms to the left:

4(y-4)+12y-(14y-1(20))=0

We add all the numbers together, and all the variables

12y+4(y-4)-(14y-120)=0

We multiply parentheses

12y+4y-(14y-120)-16=0

We get rid of parentheses

12y+4y-14y+120-16=0

We add all the numbers together, and all the variables

2y+104=0

We move all terms containing y to the left, all other terms to the right

2y=-104

y=-104/2

y=-52

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