4(y-4)+2(y+2)=12

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Solution for 4(y-4)+2(y+2)=12 equation:


Simplifying
4(y + -4) + 2(y + 2) = 12

Reorder the terms:
4(-4 + y) + 2(y + 2) = 12
(-4 * 4 + y * 4) + 2(y + 2) = 12
(-16 + 4y) + 2(y + 2) = 12

Reorder the terms:
-16 + 4y + 2(2 + y) = 12
-16 + 4y + (2 * 2 + y * 2) = 12
-16 + 4y + (4 + 2y) = 12

Reorder the terms:
-16 + 4 + 4y + 2y = 12

Combine like terms: -16 + 4 = -12
-12 + 4y + 2y = 12

Combine like terms: 4y + 2y = 6y
-12 + 6y = 12

Solving
-12 + 6y = 12

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + 6y = 12 + 12

Combine like terms: -12 + 12 = 0
0 + 6y = 12 + 12
6y = 12 + 12

Combine like terms: 12 + 12 = 24
6y = 24

Divide each side by '6'.
y = 4

Simplifying
y = 4

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