4(y-4)+2(y+2)=30

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Solution for 4(y-4)+2(y+2)=30 equation: 



4(y-4)+2(y+2)=30

We move all terms to the left:

4(y-4)+2(y+2)-(30)=0

We multiply parentheses

4y+2y-16+4-30=0

We add all the numbers together, and all the variables

6y-42=0

We move all terms containing y to the left, all other terms to the right

6y=42

y=42/6

y=7

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