4(y-4)+3(y-7)=-30

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Solution for 4(y-4)+3(y-7)=-30 equation: 



4(y-4)+3(y-7)=-30

We move all terms to the left:

4(y-4)+3(y-7)-(-30)=0

We add all the numbers together, and all the variables

4(y-4)+3(y-7)+30=0

We multiply parentheses

4y+3y-16-21+30=0

We add all the numbers together, and all the variables

7y-7=0

We move all terms containing y to the left, all other terms to the right

7y=7

y=7/7

y=1

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