4(y-4)+3=3(y+7)=-30

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Solution for 4(y-4)+3=3(y+7)=-30 equation: 



4(y-4)+3=3(y+7)=-30

We move all terms to the left:

4(y-4)+3-(3(y+7))=0

We multiply parentheses

4y-(3(y+7))-16+3=0



We calculate terms in parentheses: -(3(y+7)), so:

3(y+7)

We multiply parentheses

3y+21

Back to the equation:

-(3y+21)



We add all the numbers together, and all the variables

4y-(3y+21)-13=0

We get rid of parentheses

4y-3y-21-13=0

We add all the numbers together, and all the variables

y-34=0

We move all terms containing y to the left, all other terms to the right

y=34

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