4(y-4)-1=-7(-2y+5)-6y

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Solution for 4(y-4)-1=-7(-2y+5)-6y equation: 



4(y-4)-1=-7(-2y+5)-6y

We move all terms to the left:

4(y-4)-1-(-7(-2y+5)-6y)=0

We multiply parentheses

4y-(-7(-2y+5)-6y)-16-1=0



We calculate terms in parentheses: -(-7(-2y+5)-6y), so:

-7(-2y+5)-6y

We add all the numbers together, and all the variables

-6y-7(-2y+5)

We multiply parentheses

-6y+14y-35

We add all the numbers together, and all the variables

8y-35

Back to the equation:

-(8y-35)



We add all the numbers together, and all the variables

4y-(8y-35)-17=0

We get rid of parentheses

4y-8y+35-17=0

We add all the numbers together, and all the variables

-4y+18=0

We move all terms containing y to the left, all other terms to the right

-4y=-18

y=-18/-4

y=4+1/2

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