4(y-4)-5=-2(-8y+9)-6y

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Solution for 4(y-4)-5=-2(-8y+9)-6y equation: 



4(y-4)-5=-2(-8y+9)-6y

We move all terms to the left:

4(y-4)-5-(-2(-8y+9)-6y)=0

We multiply parentheses

4y-(-2(-8y+9)-6y)-16-5=0



We calculate terms in parentheses: -(-2(-8y+9)-6y), so:

-2(-8y+9)-6y

We add all the numbers together, and all the variables

-6y-2(-8y+9)

We multiply parentheses

-6y+16y-18

We add all the numbers together, and all the variables

10y-18

Back to the equation:

-(10y-18)



We add all the numbers together, and all the variables

4y-(10y-18)-21=0

We get rid of parentheses

4y-10y+18-21=0

We add all the numbers together, and all the variables

-6y-3=0

We move all terms containing y to the left, all other terms to the right

-6y=3

y=3/-6

y=-1/2

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