4(y-4)=4+y-8

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Solution for 4(y-4)=4+y-8 equation: 



4(y-4)=4+y-8

We move all terms to the left:

4(y-4)-(4+y-8)=0

We add all the numbers together, and all the variables

4(y-4)-(y-4)=0

We multiply parentheses

4y-(y-4)-16=0

We get rid of parentheses

4y-y+4-16=0

We add all the numbers together, and all the variables

3y-12=0

We move all terms containing y to the left, all other terms to the right

3y=12

y=12/3

y=4

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