4(y-4)=5(3y-2)

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Solution for 4(y-4)=5(3y-2) equation:



4(y-4)=5(3y-2)
We move all terms to the left:
4(y-4)-(5(3y-2))=0
We multiply parentheses
4y-(5(3y-2))-16=0
We calculate terms in parentheses: -(5(3y-2)), so:
5(3y-2)
We multiply parentheses
15y-10
Back to the equation:
-(15y-10)
We get rid of parentheses
4y-15y+10-16=0
We add all the numbers together, and all the variables
-11y-6=0
We move all terms containing y to the left, all other terms to the right
-11y=6
y=6/-11
y=-6/11

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