4(y-4)=6(3y+2)

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Solution for 4(y-4)=6(3y+2) equation: 



4(y-4)=6(3y+2)

We move all terms to the left:

4(y-4)-(6(3y+2))=0

We multiply parentheses

4y-(6(3y+2))-16=0



We calculate terms in parentheses: -(6(3y+2)), so:

6(3y+2)

We multiply parentheses

18y+12

Back to the equation:

-(18y+12)



We get rid of parentheses

4y-18y-12-16=0

We add all the numbers together, and all the variables

-14y-28=0

We move all terms containing y to the left, all other terms to the right

-14y=28

y=28/-14

y=-2

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