4(y-5)+2y=28

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Solution for 4(y-5)+2y=28 equation: 



4(y-5)+2y=28

We move all terms to the left:

4(y-5)+2y-(28)=0

We add all the numbers together, and all the variables

2y+4(y-5)-28=0

We multiply parentheses

2y+4y-20-28=0

We add all the numbers together, and all the variables

6y-48=0

We move all terms containing y to the left, all other terms to the right

6y=48

y=48/6

y=8

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