4(y-5)+3(y+2)=28

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Solution for 4(y-5)+3(y+2)=28 equation: 


Simplifying
4(y + -5) + 3(y + 2) = 28

Reorder the terms:
4(-5 + y) + 3(y + 2) = 28
(-5 * 4 + y * 4) + 3(y + 2) = 28
(-20 + 4y) + 3(y + 2) = 28

Reorder the terms:
-20 + 4y + 3(2 + y) = 28
-20 + 4y + (2 * 3 + y * 3) = 28
-20 + 4y + (6 + 3y) = 28

Reorder the terms:
-20 + 6 + 4y + 3y = 28

Combine like terms: -20 + 6 = -14
-14 + 4y + 3y = 28

Combine like terms: 4y + 3y = 7y
-14 + 7y = 28

Solving
-14 + 7y = 28

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '14' to each side of the equation.
-14 + 14 + 7y = 28 + 14

Combine like terms: -14 + 14 = 0
0 + 7y = 28 + 14
7y = 28 + 14

Combine like terms: 28 + 14 = 42
7y = 42

Divide each side by '7'.
y = 6

Simplifying
y = 6

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