4(y-5)+3=3(3y+1)

Solution for 4(y-5)+3=3(3y+1) equation:

4(y-5)+3=3(3y+1)

We move all terms to the left:

4(y-5)+3-(3(3y+1))=0

We multiply parentheses

4y-(3(3y+1))-20+3=0


We calculate terms in parentheses: -(3(3y+1)), so:

3(3y+1)

We multiply parentheses

9y+3

Back to the equation:

-(9y+3)


We add all the numbers together, and all the variables

4y-(9y+3)-17=0

We get rid of parentheses

4y-9y-3-17=0

We add all the numbers together, and all the variables

-5y-20=0

We move all terms containing y to the left, all other terms to the right

-5y=20

y=20/-5

y=-4