4(y-5)=3y+12-y

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Solution for 4(y-5)=3y+12-y equation: 



4(y-5)=3y+12-y

We move all terms to the left:

4(y-5)-(3y+12-y)=0

We add all the numbers together, and all the variables

4(y-5)-(2y+12)=0

We multiply parentheses

4y-(2y+12)-20=0

We get rid of parentheses

4y-2y-12-20=0

We add all the numbers together, and all the variables

2y-32=0

We move all terms containing y to the left, all other terms to the right

2y=32

y=32/2

y=16

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