4(y-5)=7(2y-5)

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Solution for 4(y-5)=7(2y-5) equation: 



4(y-5)=7(2y-5)

We move all terms to the left:

4(y-5)-(7(2y-5))=0

We multiply parentheses

4y-(7(2y-5))-20=0



We calculate terms in parentheses: -(7(2y-5)), so:

7(2y-5)

We multiply parentheses

14y-35

Back to the equation:

-(14y-35)



We get rid of parentheses

4y-14y+35-20=0

We add all the numbers together, and all the variables

-10y+15=0

We move all terms containing y to the left, all other terms to the right

-10y=-15

y=-15/-10

y=1+1/2

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