4(y-6)=2(y-12)+2y

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Solution for 4(y-6)=2(y-12)+2y equation: 



4(y-6)=2(y-12)+2y

We move all terms to the left:

4(y-6)-(2(y-12)+2y)=0

We multiply parentheses

4y-(2(y-12)+2y)-24=0



We calculate terms in parentheses: -(2(y-12)+2y), so:

2(y-12)+2y

We add all the numbers together, and all the variables

2y+2(y-12)

We multiply parentheses

2y+2y-24

We add all the numbers together, and all the variables

4y-24

Back to the equation:

-(4y-24)



We get rid of parentheses

4y-4y+24-24=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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