4(y-6)=3y+12

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Solution for 4(y-6)=3y+12 equation: 



4(y-6)=3y+12

We move all terms to the left:

4(y-6)-(3y+12)=0

We multiply parentheses

4y-(3y+12)-24=0

We get rid of parentheses

4y-3y-12-24=0

We add all the numbers together, and all the variables

y-36=0

We move all terms containing y to the left, all other terms to the right

y=36

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