4(y-7)+8y=32

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Solution for 4(y-7)+8y=32 equation: 



4(y-7)+8y=32

We move all terms to the left:

4(y-7)+8y-(32)=0

We add all the numbers together, and all the variables

8y+4(y-7)-32=0

We multiply parentheses

8y+4y-28-32=0

We add all the numbers together, and all the variables

12y-60=0

We move all terms containing y to the left, all other terms to the right

12y=60

y=60/12

y=5

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