4(y-7)-2=-4(-4y+4)-2y

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Solution for 4(y-7)-2=-4(-4y+4)-2y equation: 



4(y-7)-2=-4(-4y+4)-2y

We move all terms to the left:

4(y-7)-2-(-4(-4y+4)-2y)=0

We multiply parentheses

4y-(-4(-4y+4)-2y)-28-2=0



We calculate terms in parentheses: -(-4(-4y+4)-2y), so:

-4(-4y+4)-2y

We add all the numbers together, and all the variables

-2y-4(-4y+4)

We multiply parentheses

-2y+16y-16

We add all the numbers together, and all the variables

14y-16

Back to the equation:

-(14y-16)



We add all the numbers together, and all the variables

4y-(14y-16)-30=0

We get rid of parentheses

4y-14y+16-30=0

We add all the numbers together, and all the variables

-10y-14=0

We move all terms containing y to the left, all other terms to the right

-10y=14

y=14/-10

y=-1+2/5

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