4(y-7)=2(6-y)+4y

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Solution for 4(y-7)=2(6-y)+4y equation: 



4(y-7)=2(6-y)+4y

We move all terms to the left:

4(y-7)-(2(6-y)+4y)=0

We add all the numbers together, and all the variables

4(y-7)-(2(-1y+6)+4y)=0

We multiply parentheses

4y-(2(-1y+6)+4y)-28=0



We calculate terms in parentheses: -(2(-1y+6)+4y), so:

2(-1y+6)+4y

We add all the numbers together, and all the variables

4y+2(-1y+6)

We multiply parentheses

4y-2y+12

We add all the numbers together, and all the variables

2y+12

Back to the equation:

-(2y+12)



We get rid of parentheses

4y-2y-12-28=0

We add all the numbers together, and all the variables

2y-40=0

We move all terms containing y to the left, all other terms to the right

2y=40

y=40/2

y=20

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