4(y-8)-4=-5(-5y+4)-3y

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Solution for 4(y-8)-4=-5(-5y+4)-3y equation: 



4(y-8)-4=-5(-5y+4)-3y

We move all terms to the left:

4(y-8)-4-(-5(-5y+4)-3y)=0

We multiply parentheses

4y-(-5(-5y+4)-3y)-32-4=0



We calculate terms in parentheses: -(-5(-5y+4)-3y), so:

-5(-5y+4)-3y

We add all the numbers together, and all the variables

-3y-5(-5y+4)

We multiply parentheses

-3y+25y-20

We add all the numbers together, and all the variables

22y-20

Back to the equation:

-(22y-20)



We add all the numbers together, and all the variables

4y-(22y-20)-36=0

We get rid of parentheses

4y-22y+20-36=0

We add all the numbers together, and all the variables

-18y-16=0

We move all terms containing y to the left, all other terms to the right

-18y=16

y=16/-18

y=-8/9

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