4(z+1)=2(z+1+6)

Solution for 4(z+1)=2(z+1+6) equation:

4(z+1)=2(z+1+6)

We move all terms to the left:

4(z+1)-(2(z+1+6))=0

We add all the numbers together, and all the variables

4(z+1)-(2(z+7))=0

We multiply parentheses

4z-(2(z+7))+4=0


We calculate terms in parentheses: -(2(z+7)), so:

2(z+7)

We multiply parentheses

2z+14

Back to the equation:

-(2z+14)


We get rid of parentheses

4z-2z-14+4=0

We add all the numbers together, and all the variables

2z-10=0

We move all terms containing z to the left, all other terms to the right

2z=10

z=10/2

z=5