4(z+1)=2(z+3)

Solution for 4(z+1)=2(z+3) equation:

Simplifying
4(z + 1) = 2(z + 3)

Reorder the terms:
4(1 + z) = 2(z + 3)
(1 * 4 + z * 4) = 2(z + 3)
(4 + 4z) = 2(z + 3)

Reorder the terms:
4 + 4z = 2(3 + z)
4 + 4z = (3 * 2 + z * 2)
4 + 4z = (6 + 2z)

Solving
4 + 4z = 6 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
4 + 4z + -2z = 6 + 2z + -2z

Combine like terms: 4z + -2z = 2z
4 + 2z = 6 + 2z + -2z

Combine like terms: 2z + -2z = 0
4 + 2z = 6 + 0
4 + 2z = 6

Add '-4' to each side of the equation.
4 + -4 + 2z = 6 + -4

Combine like terms: 4 + -4 = 0
0 + 2z = 6 + -4
2z = 6 + -4

Combine like terms: 6 + -4 = 2
2z = 2

Divide each side by '2'.
z = 1

Simplifying
z = 1