4(z+1)=3(z+2)

Solution for 4(z+1)=3(z+2) equation:

Simplifying
4(z + 1) = 3(z + 2)

Reorder the terms:
4(1 + z) = 3(z + 2)
(1 * 4 + z * 4) = 3(z + 2)
(4 + 4z) = 3(z + 2)

Reorder the terms:
4 + 4z = 3(2 + z)
4 + 4z = (2 * 3 + z * 3)
4 + 4z = (6 + 3z)

Solving
4 + 4z = 6 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
4 + 4z + -3z = 6 + 3z + -3z

Combine like terms: 4z + -3z = 1z
4 + 1z = 6 + 3z + -3z

Combine like terms: 3z + -3z = 0
4 + 1z = 6 + 0
4 + 1z = 6

Add '-4' to each side of the equation.
4 + -4 + 1z = 6 + -4

Combine like terms: 4 + -4 = 0
0 + 1z = 6 + -4
1z = 6 + -4

Combine like terms: 6 + -4 = 2
1z = 2

Divide each side by '1'.
z = 2

Simplifying
z = 2