4(z+1)=36

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Solution for 4(z+1)=36 equation: 



4(z+1)=36

We move all terms to the left:

4(z+1)-(36)=0

We multiply parentheses

4z+4-36=0

We add all the numbers together, and all the variables

4z-32=0

We move all terms containing z to the left, all other terms to the right

4z=32

z=32/4

z=8

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